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Naval Architect Brain Teaser


Ewen

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Another question asked during newbie interrogation here at work...

 

A barge loaded with concrete blocks is floating in a tank full of fresh water.

Including its cargo, the barge has a displacement of 300 tonnes (300,000 kg).

The barge unloads five concrete blocks, each weighing 10 tonnes (10,000 kg) into the tank of water.

 

Does the water level in the tank go up, down, or stay the same ?

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if you mean water level on the boat it stays the same, if you mean water level on the glass it goes down.

 

how can it stay the same on the boat? :confused:

 

surely if you remove blocks from the boat it would be lighter, displace less water and thus sit higher in the water?

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I think the boat will now sit higher in the water due to less weight. Therefore it will now displace less water so the water level on the side of the tank will go down.

 

Edit: Just read it again and noticed the blocks are going to be placed into the water :( 1 litre of water weighs 1 kg, therefore the weight removed will in relation displace the same volume of water when placed in the tank. Water level on tank remains the same.

 

I think lol

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I'd say it stays the same, unless there's some odd thing about mass and displacement, i.e. the concrete blocks in the barge are above water and it's their weight, not their mass, thats causing the barge to displace water.

That's probably all bollocks though.

 

 

What if the concrete absorbs water?

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I think that 10T of mass on a boat will displace 10T (equivalent) of water.

Take it off and the water level will drop by however far 10T of water is (dependant on the size of the tank etc obviously).

Put it back in the water and it still displaces 10T of water, the same as before, so the water level will go back up to where it was, the boat will be higher in the water than before (by 10Ts worth of water in the shape/volume of the bottom of the boat).

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I think that 10T of mass on a boat will displace 10T (equivalent) of water.

Take it off and the water level will drop by however far 10T of water is (dependant on the size of the tank etc obviously).

Put it back in the water and it still displaces 10T of water, the same as before, so the water level will go back up to where it was, the boat will be higher in the water than before (by 10Ts worth of water in the shape/volume of the bottom of the boat).

 

That's what I think but it can't be that easy can it? There must be a catch.

 

 

No-one mention the Jet-plane on the conveyor belt runway!

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Its not a trick question, knowledge of boats not necessary.

Couple of you have the right idea....bonus points if you can explain your answer.

Clue 1...boat floats, boat carrying concrete floats too, but concrete sinks.

Clue 2...1 cubic metre of fresh water weighs (approx) 1000 kg...1 cubic metre of concrete weighs (for the sake of this exercise) 2500 kg.

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I'm assuming that you can answer this fully with the inf given, but I'm getting stuck on the fact that while in the barge the blocks will be displacing a mass of water equal to thier own mass (i.e. a greater volume than their own) but once in the water they will sink and so displace a volume of water equal to their own.

 

So the blocks displave more water while they are still in the barge, and less when they are in the water. Also the barge displaces less water when the blocks are off loaded.

 

Holy moly - thats it. The water level will drop. Because both the barge and the blocks are displacing less water.

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It is the volume of an object that determines the amount of water that the object displaces.

 

Clue 2...1 cubic metre of fresh water weighs (approx) 1000 kg...1 cubic metre of concrete weighs (for the sake of this exercise) 2500 kg.

Basically you're swapping water for concrete?

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